Subnetting Kelas B

SUBNETTING KELAS B


Diketahui sebuah IP dengan nomor 176.16.0.0/19
(KELAS B)
ditanya :

A.Berapa Nomor Subneting ?
B.berapa Nomor Broadcast ?
C.berapa IP yang diijinkan ?

JWB:

176.16.0.0/19 =
11111111.11111111.11100000.00000000

A. Jumlah Network = 23 = 8.
dapat 3 dari jumlah bit 1.

B. Jumlah HOST = 213 jumlah bit 0 = 8192
Dapat 14 dari jumplah bit 0

C. Jumlah blog IP = 256 - 224 = 32
Dapat 224 dari 11100000 (di binerkan)



Subnet = 176.16.0.0
Broadcast= 176.16.31.255

Subnet = 176.16.32.0
Broadcast=176.16.63.255.

Subnet = 176.16.64.0
Broadcast= 176.16.95.255

Subnet = 176.16.96.0
Broadcast= 176.16.127.255

Subnet=176.16.128.0
Broadcast=176.16.159.255

Subnet=176.16.160.0
Broadcast=176.16.181.255

Subnet=176.16.182.0
Broadcast=176.16.113.255

Subnet=176.16.224.0
Broadcast=176.16.124.255


IP yang diijinkan
176.16.0.1176.16.63.254 176.16.32.1 176.16. 176.16. 176.16.






176.16. 176.16. 176.16.